Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    uint8_t reverse_val=0x00;
    for (int i=0 ; i<4 ; i++){
        reverse_val|=((val>>i)&1)<<(7-i);
        reverse_val|=((val>>(7-i))&1)<<i;
    } 
    return reverse_val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach