Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    // shift left 
    for (uint8_t i= 0;i<4 ; i++)
    {
        // extract 
        uint8_t value1 = (val>>i)& 0x01;
        // extract
        uint8_t value2 = (val >>(8-(i+1)) & 0x01);
        
        //set
        val &= ~(1 <<(8-(i+1)));
        val |=  value1<< (8-(i+1));

        // set
        val &= ~( 1<<i);
        val|=(value2 << i);
        
    }
    return val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach