Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>


uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    uint8_t temp =0;
    for (int i=0;i<8;i++)
    {  
        temp =  (temp <<1)| (val&1);
         
        val = val >>1;
       
    }
 
    return  temp;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach

here when i use while loop , for leading zero ip , op is wrong

 

 

Upvote
Downvote
Loading...

Input

26

Expected Output

88