Bit Reversal in an 8-bit Value

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    int bit = 0;
    int reg =0 ;
    for ( int i = 0; i < 8; i++){
    bit = ( val >> i ) & 1;
    reg = reg | (bit << (7 - i));
    
    }
    // Your logic here
    return reg;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}