Bit Reversal in an 8-bit Value

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    uint8_t value = 0;

    for (int i = 0; i < 8; i++) 
    {
        // Shift value left to make room for next bit
        value <<= 1;

        // Take LSB from input and add to value
        value |= (val & 1);

        // Shift input right to process next bit
        val >>= 1;
    }

    return value;
   
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}