Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    uint8_t l = 0, h =8-1;
    while(l<h){
        if(((val>>h)&1) != ((val>>l)&1)){
            val ^= (1<<h)|(1<<l);
        }
        l++;h--;
    }
    return val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach