Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    val = ((val & 0xF0) >> 4)|((val&0x0F)<<4); 
    val = ((val & 0xCC) >> 2)|((val&0x33)<<2);
    val = ((val & 0xAA) >> 1)|((val&0x55)<<1);
    return val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach