Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    val = ((val & 0x55) << 1) | ((val & (0x55 << 1)) >> 1);
    val = ((val & 0x33) << 2) | ((val & (0x33 << 2)) >> 2);
    val = ((val & 0x0F) << 4) | ((val & (0x0F << 4)) >> 4);// Your logic here
    return val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach