Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    for(int i=0; i<4; i++)
    {
        uint8_t temp_l, temp_h;
        temp_l = ((val>>i) & 0x1);
        temp_h = ((val>>(7-i)) & 0x1);

        val &= ~(1<<i);
        val &= ~(1<<(7-i));

        val |= (temp_h << i);
        val |= (temp_l << (7-i));
    }
    return val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach