Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    uint8_t new_val=0;
    for(int i=0; i<4; i++){
        new_val |= (((val >> (8-i-1))&1)<<i);
        new_val |= (((val >> i)&1)<<(8-i-1));
        //printf("%d \n",new_val);
    }
    return new_val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach