Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    uint8_t temp = 0;
    for(int i = 0; i < 4; i++) {
        int mask1 = (1 << (3-i)) & val;
        int mask2 = (1 << (4+i)) & val;
        temp |= mask1 << ((i*2)+1);
        temp |= mask2 >> ((i*2)+1);
    }
    return temp;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach