Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    int res = 0;
    for( int i =0; i < 8 ;i ++)
    {
        int bit = (val >> i ) & 1;
        res |= (bit << 7 - i);
    }
    return res;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach