Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    for(int i=0; i<4; i++)
    {
        uint8_t first_bit = (val>>i)&0x01;
        uint8_t last_bit =  (val>>(7-i))&0x01;
        val &= ~(1<<(7-i));
        val &= ~(1<<i);
        val |= (first_bit<<(7-i));
        val |= (last_bit<<i);
        // printf("%d %d %d \n",first_bit,last_bit,val);
        // if(i==1)return val;    
    }
    return val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach

 

 

 

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Input

26

Expected Output

88