Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    uint8_t bit = 1;
    uint8_t reverse = 0;
    for (int i = 0; i < 8; i++)
    {
        reverse |= ((val & bit) >> i) << 7-i;
        bit <<= 1;
    }
    return reverse;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach

 

 

 

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Input

26

Expected Output

88