Bit Reversal in an 8-bit Value

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here

    uint8_t output = 0;
    for(int i=0;i<8;i++){
        output <<=1; //Shift output reg << so LSB's go to end/left(reversed)
        output |= (val & 1); //Add current LSB of val to output
        val >>=1; //Shift val to right to get next bit
    }
    return output;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}