Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    val = (val >> 4) | (val << 4);
    val = ((val & 0b11001100) >> 2) | ((val & 0b00110011) << 2);
    val = ((val & 0b10101010) >> 1) | ((val & 0b01010101) << 1);
    return val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach