Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    uint8_t reversed = 0;
    uint8_t curr;
    
    for(int i=0; i<8; i++){
        curr = val >>(7-i) & 0x01  ;
        reversed |= curr<<i;
    }
    return reversed;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach