Bit Reversal in an 8-bit Value

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t reg) {
    // Your logic here
    int end = 7;
    for(int i=0; i<4; i++){
        if(((reg >> i) & 1u) != ((reg >> end) & 1u)){
            reg ^= (1u << i);
            reg ^= (1u << end);
        }
        end--;
    }

    return reg;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}