Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    uint8_t left=0,right=7;
    while(left<right)
    {
      if(((val>>left)&1)!=((val>>right)&1))
      {
        val^=(1<<left);
        val^=(1<<right);
      }
      right--;
      left++;
    }
    return val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach