Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

#define MAX_BIT_LEN     (8)

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    uint8_t temp_reg = 0;
    for(uint8_t i = 0; i < MAX_BIT_LEN; i++){
        temp_reg <<= 1;
        temp_reg |= (val & 0x01u);
        val >>= 1;
    }
    return temp_reg;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach

 

 

 

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Input

26

Expected Output

88