Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    uint8_t mask = 0x01;
    for(uint8_t i = 0 ; i < 4 ;i++)
    {
        if(((val >> i)& 1 == 1 ) != ( (val >> (7-i))& 1 == 1) )
        {
            val ^= (mask << i);
            val ^= (mask << (7 - i) );
        }
    }
    return val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach