Bit Reversal in an 8-bit Value

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    uint8_t a=0,b=256;
    for(int i=0;i < 8 ;i++){
        uint8_t bit = (val >> i) & 1;      
        a |= bit << (7 - i);
    }
    // Your logic here
    return a;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}