Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    val = (val & 0b11110000)>>4 | (val & 0b00001111)<<4 ;
    val = (val & 0b11001100)>>2 | (val & 0b00110011)<<2;
    val = (val & 0b10101010)>>1 | (val & 0b01010101)<<1;
    return val;

}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach