Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    val  = (( val & 0x0F ) << 4 ) | (( val & 0xF0 ) >> 4);
    val  = (( val & 0xCC ) >> 2 ) | (( val & 0x33 ) << 2);
     val  = (( val & 0xAA ) >> 1 ) | (( val & 0x55 ) << 1);
    return val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach