Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    uint8_t result= 0;
    // Your logic here
    for (int i=0; i<8; i++){
        uint8_t bit = val & 1;
        result <<= 1; // Started with all 0, we need to shift to make space.
        result |= bit;  // take the new value
        val >>= 1;
    }
    return result;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach