Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here


    int mask_1=1;
    int mask_2=1;
    int val_1=1;
    int val_2=1;
    int new_Val=0;
    for(int i= 0; i<=7; i++)
    {   
        mask_1=1<<i;
        
        val_1=(mask_1&val)>>(i);

        if (val_1==1)
        {
            new_Val=new_Val|(1<<7-i);
        }

        

        // printf("%d,%d\n",val_1,val_2);

        
    }
    return new_Val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach