Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    uint8_t res = 0;
    res = ((val & 1)<<7) | ((val & 0b10)<<5) | ((val & 0b100)<<3) |((val & 0b1000)<<1) | (((val & 0b10000)>>1)) | (((val & 0b100000)>>3)) | (((val & 0b1000000)>>5)) | (((val & 0b10000000)>>7));

    return res;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach