Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

// Input: val = 0b00011010
// Output: 0b01011000 → Decimal: 88

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    uint8_t reverse = 0;
    for(int i = 0; i < 8; i++){
        reverse <<= 1;   // Shift left to make space for the next bit   
        reverse |= (val & 1);
        val >>= 1;
    }
    return reverse;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach