Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    uint8_t result=0;
    for(int i=0;i<8;i++)
    {
        if(((val>>i)&1)==1)
            result |= (1<<(7-i)); //Figure out why I used 7 and boom , you cracked the logic !
    }
    return result;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach