Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    uint8_t temp=0;
    
    for(int i=1; i<=8;i++){
        temp = temp|(((val&(1<<(8-i)))>>(8-i))<<(i-1));
    }
    return temp;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach