Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    uint8_t result=0;
    for (int i=0; i<4; i++) {
        uint8_t right = ((val>>i) & 1U)<<(7-i);
        uint8_t left = ((val>>7-i) & 1U)<<i;
        result = result | right | left;
    }
    return result;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach