Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    int n=7;
    uint8_t res=0;
    for(int i=0; i<8; i++)
    {
        if(val & (1<<i))
        {
            res |= (1<< (n-i));
        }
            
    }
    return res;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach