Bit Reversal in an 8-bit Value

Code

// bit reversal


#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    val=(val<<4)|(val>>4);
    val=((val&0xcc)>>2)|((val&0x33)<<2);
    val=((val&0xaa)>>1)|((val&0x55)<<1);

    
    return val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach