Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    if (val == 0) return 0;
    uint8_t mask = 0x00;
    uint8_t result = 0x00;
    //uint8_t shift = 0x80;
    for(uint8_t x=0; x < 8; x++)
    {
        //shift to left then compare for mas result
        mask = (1 & (val >> x));
        result |= (mask << 7 - x);
    }
    return result;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach