Bit Reversal in an 8-bit Value

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    uint8_t bit=0;
    uint8_t r_val=0;
    for (unsigned int i=0; i < 8; i++){
        bit = val & 0X01;
        val >>=1;
        r_val |= (bit & 0x01) << (8-(i+1));
    }
    return r_val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}