Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    val = val<<4 | val>>4;
    val = ((val << 2 | val >> 6) & 0xDD) | ((val >> 2 | val << 6) & 0x33);
    val = ((val << 1 | val >> 7) & 0xAA) | ((val >> 1 | val << 7) & 0x55);
    
    return val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach