Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic heu
    uint8_t res = 0;

    for(int i = 0;i<8;i++){

        res <<= 1;
        res |= (val & 1);
        val >>=1;
        
    }
    
    return res;
}
//(reg >> n) | (reg << (32-n)
int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach