Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    // nibble reverse
    uint8_t tmp = ((val & 0xF0 ) >> 4)| ((val & 0x0F) << 4);
    // pair of 2 swap
    tmp = ((tmp & 0xCC ) >> 2) | ((tmp & 0x33) << 2);
    // individual bits swap
    tmp = ((tmp & 0xAA ) >> 1) | ((tmp & 0x55) << 1);
    return tmp;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach