Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    uint8_t val1 = 0;
    uint8_t val2 = 0;
    uint8_t shift = 7;
    for (int i=0; i<8; i++) {
      val2 = val & 1;
      val1 |= (val2 << shift);
      val >>= 1;
      shift--;
    }
    return val1 & 0xFF;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach