Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    int i,j,k,l;
    for(i=0,j=7;i<j;i++,j--)
    {
        k=val>>i&1;
        l=val>>j&1;
        if(k!=l)
        {
            val=val^(1<<i);
            val=val^(1<<j);
        }
    }
    return val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach