Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
val = ((val&0x0f)<<4)|((val&0xf0)>>4);
val = ((val&0x33)<<2)|((val&0xcc)>>2);
val = ((val&0x55)<<1)|((val&0xaa)>>1);
return val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach