Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    uint8_t x = val;
    x = ((x & 0xF0)>> 4)|((x & 0x0F)<< 4);
    x = ((x & 0xCC)>> 2)|((x & 0x33)<< 2);
    x = ((x & 0xAA)>> 1)|((x & 0x55)<< 1);
    return x;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach