Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    uint8_t result = 0;
    uint8_t mask = 1U << 8 * sizeof(val) - 1;
    while (val) {
        if(val & 0x1) {
            result |= mask;
        }
        mask >>= 1;
        val >>= 1;
    }
    return result;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach