Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    uint8_t tmp, out = 0;
    tmp = val & 1; tmp <<= 7; out |= tmp; val >>= 1;
    tmp = val & 1; tmp <<= 6; out |= tmp; val >>= 1;
    tmp = val & 1; tmp <<= 5; out |= tmp; val >>= 1;
    tmp = val & 1; tmp <<= 4; out |= tmp; val >>= 1;
    tmp = val & 1; tmp <<= 3; out |= tmp; val >>= 1;
    tmp = val & 1; tmp <<= 2; out |= tmp; val >>= 1;
    tmp = val & 1; tmp <<= 1; out |= tmp; val >>= 1;
    tmp = val & 1; out |= tmp;
    return out;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach