Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    uint8_t x=0,b = val;
    int a =0;
    for(int i =0 ; i<8; i++){
      b = val >> (i);
      a = (b & 0x01);
      x = x | (a<<(7-i));
    }
    return x;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach