Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here

     uint8_t res = 0;
     
    for(uint8_t i=0;i<=7;i++)
    {
       res <<= 1U;          // Shift result left
        res |= (val & 1U);   // Copy the LSB of val to result's LSB
        val >>= 1U;             // Shift val right to process the next bit
       
    }
    return res;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach