Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    uint8_t reg = val;

    uint8_t rev =0;
    int last;
    int i=7;
    

    while(reg>0){

        
        last = (reg & (0x01));
        rev |=(last<<i);
        reg = reg >> 1;
        i--;
    }
    return rev;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach