Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>


uint8_t reverse_bits(uint8_t val) {
    int tmp = 0;
    for(int i = 0; i < 4; i++){
        tmp |= (((val >> i )&1) << (7-i));
        tmp |= (((val >> (7-i))&1) << (i));
    }
    return tmp;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach