Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>
uint8_t reverse_bits(uint8_t val) {
    uint8_t result = 0;
    for(int i=0;i<8;i++)
    {
        if(val & (1<<i))
        {
            result |= (1<<(7-i));
        }
    }
    return result;
}
int main() 
{
    uint8_t val;
    scanf("%hhu", &val);
    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach