Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
   int new_val =0;
   for(int i=7;i>=0;i--)
   {
    new_val<<=1;
    new_val|=(val&1);
    val>>=1;
   
   }
    return new_val;


}
int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach